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Do I have a legitimate shortcut for finding the area under a curve?

By Emma Martinez โ€ข
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I'm studying functions, and recently I've spent some time looking into finding the area under a parabolic curve with integral calculus.

The methods I've found in this regard are very straightforward, though (and this must be because of a limited knowledge of more advanced methods) I find the solution can take quite some time to write up.

I've toyed around with what seems to be a very simple setup to get an accurate solution to the area under a curve, as well as the area between a curve and a right triangle...

Sketch of the parabola

Parabola represents 1/4๐‘ฅ^2
๐‘ฅ1 = 0 units
๐‘ฆ1 = 0 units
๐‘ฅ2 = 5 units
๐‘ฆ2 = 1/4(5)^2 = 6.25 units

Regarding one-half of the figure above:

Area of the rectangle, R; from ๐‘ฅ = 0 to ๐‘ฅ = 5; to ๐‘ฆ = 6.25:
๐ด = ๐‘™ โˆ— ๐‘ค
๐ด = 6.25 โˆ— 5
๐ด = 31.25 units

Area of the triangle; A:
๐ด = 1/2 โˆ— ๐‘ โˆ—โ„Ž
๐ด = 1/2 โˆ— 5 โˆ— 6.25
๐ด = 15.625 units

Area of under-curve; B:
๐ด๐‘‡ = ๐ด1 + ๐ด2
๐ด๐‘‡ = 1/6 โˆ— 2(๐‘ฅ2 โˆ’ ๐‘ฅ1) โˆ— (๐‘ฆ2 โˆ’ ๐‘ฆ1) + (๐‘ฆ1 โˆ— ๐‘ฅ2)
๐ด๐‘‡ = 1/6 โˆ— 2(5 โˆ’ 0) โˆ— (6.25 โˆ’ 0) + (0 โˆ— 5)
๐ด๐‘‡ = 1/6 โˆ— (10) โˆ— (6.25) + (0)
๐ด๐‘‡ = 10.41666667 units

Derived from Archimedesโ€™ assertion that the area of the inside of a parabola is equal to 2/3๐‘โ„Ž. ๐ด2 describes the addition of the area of an inner rectangle that would result from a vertical phase shift; for example, a positive c-value in the form ๐‘Ž๐‘ฅ^2+๐‘๐‘ฅ+๐‘. In this case, ๐‘ฆ1 begins at a number >0, which creates a rectangle directly under the bottom edge of section B.

Area of the space between the triangle and curve; C:
๐ด๐ถ = ๐‘… โˆ’ (๐ด + ๐ต)
๐ด๐ถ = 31.25 โˆ’ (15.625 + 10.41666667)
๐ด๐ถ = 5.20833333 units

2/3๐‘โ„Ž is 2/3 of the area of the triangle, and 1/3 of the area of the rectangle.

The area of C is proportionate to 5.20833333/15.625 = 1/3 of the area of A.

The area of C is proportionate to 5.20833333/10.41666667 = 1/2 of the area of B.

Equation for determining the area of C:
๐ด = 1/6๐‘โ„Ž
๐ด = 1/6(5)(6.25)
๐ด = 5.208333333 units

I'm very sorry if the formatting doesn't work out for this post. I'm not used to the layout, nor am I (as you can tell) a very effective communicator of math (haha). Unless there's a '^' involved, any number following a variable is meant as subscript. I will re-post more carefully or email a .pdf to anybody who may have any problems wading through this. Thank you for any advice and tips!

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