Find rank and nullity of a matrix.
$\endgroup$ 1To find: rank $A$ and nullity $A$ for $$A=\begin{pmatrix} 0 &0 &0 \\ 0 & 0.5&-0.5 \\ 0&-0.5 & 0.5 \end{pmatrix}$$ I know the nullity refers to the number of free variables in the matrix and the rank refers to the $dim(columnspace)$; where to from here?
2 Answers
$\begingroup$More Generally. First you are going to want to set this matrix up as an Augmented Matrixwhere $Ax=0$.
$1)$ To find the rank, simply put the Matrix in REF or RREF
$\left[\begin{array}{ccc|c} 0 & 0 & 0 &0 \\ 0 & 0.5 & -0.5 & 0 \\ 0 & -0.5 & 0.5 & 0 \end{array}\right] \longrightarrow RREF \longrightarrow \left[\begin{array}{ccc|c} 0 & 0 & 0 &0\\ 0 & 0.5 & -0.5 & 0\\ 0 & 0 & 0 & 0 \end{array}\right] $
Seeing that we only have one leading variable we can now say that the rank is 1.
$2)$ To find nullity of the matrix simply subtract the rank of our Matrix from the total number of columns.
So:
Null (A)=3 - 1=2
Hope this is helpful.
$\endgroup$ $\begingroup$The matrix has one linearly independent row (take the negative of the second to get the third) implying that the rank is 1 and the nullity is 2.
$\endgroup$
