M BUZZ CRAZE NEWS
// general

Find the maximum rate of change of a multivariable function

By John Parsons
$\begingroup$

So i have this function:

$$f(x,y,z) = 4x^3yz^2+2xz^3+xyz$$

And the question is: What is the direction u for this directional derivative $f'(u,(1,-1,-1))$ to be maximal and what is the direction u for this directional derivative?

I know that $\bigtriangledown f|(1,-1,-1)=(-13,3,13)$, should i just do $\sqrt{-13^2+3^2+13^2}$?

if not, what is the correct way to do it?

Thank you

$\endgroup$ 1

1 Answer

$\begingroup$

You are correct. The gradient at a point will give you the direction of maximum increase in the value of the function. Its direction will be $\frac{\nabla f}{|\nabla f|}$ In your case:

$$\nabla f = (12x^2yz^2+2z^3+yz,4x^3z^2+xz,8x^3yz+6xz^2+xy)$$

Therefore,

$$\nabla f(1,-1,-1) = (-13,3,13)$$

As you have already calculated.

It's direction would be $$\frac{(-13,3,13)}{\sqrt{2(13^2)+9}} \approx (-0.698,0.161,0.698)$$

$\endgroup$ 9

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy