How do I prove that an anti-symmetric matrix $A$ is not invertible? [duplicate]
By Daniel Rodriguez •
$A$ is a square anti symmetric matrix with dimension $n\times n$.
It is known that $n$ is an odd number. Prove that $A$ is not invertible.
How do I prove this? any hints please?
$\endgroup$ 01 Answer
$\begingroup$$$\det(A)=\det(A^T)=\det(-A)=(-1)^n\det(A)=-\det(A)$$ since $n$ is odd. hence $$\det(A)=0$$
$\endgroup$ 3More in general
‘Cutter’s Way’ (March 20, 1981)