If a coin tossed for $3$ times what is the probability of getting all tails?
If a coin tossed for $3$ times what is the probability of getting all tails?
Is $\frac{1}{8}$ the right answer?
$\endgroup$ 23 Answers
$\begingroup$Yes.
If the coin is fair, then the odds of getting heads or tails should be equal, $\frac{1}{2}$.
Then 3 tosses of tails will have a chance of $\frac{1}{2} \cdot \frac{1}{2} \cdot \frac{1}{2} = \frac18$.
$\endgroup$ $\begingroup$Tossing of the coin is an independent event. The probablility of each event is $\frac{1}{2}.$ Hence, the desired probability is $$\frac{1}{2}.\frac{1}{2}.\frac{1}{2}=\frac{1}{8}.$$
$\endgroup$ $\begingroup$No, the right answer is 1/4
The reasoning towards this is that tossing the coin three times could give the following combinations:
H = Heads
T = Tails
T , T , T
T , T , H
T , H , T
T , H , H
H , H , H
H , H , T
H , T , H
H , T , T
Total Combinations = 8
3 Consecutive Tails/Heads = 2
Answer = 2/8 = 1/4
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