Remove the first part of each line of a text file

I am trying to edit a text file which has multiple lines that look like this:

avaya logs 20171202 000000 (9).txt: 660119211mS CMLOGGING: CALL:2017/12/0111:14,00:00:16,008,203,O,208,208,Jon,,,1,,""n/a,0

I want to remove everything before where it says CALL on every line.
I think the sed command can do this but I am not very familiar with it.
How can I do this?

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2 Answers

You can use awk in the following way:

awk -F "CALL" '{print "CALL"$2}' filename 

The result is:

CALL:2017/12/0111:14,00:00:16,008,203,O,208,208,Jon,,,1,,""n/a,0

Details:

1. Use the -F or --field-separator flag, and setting CALL to be the field seperator
2. Print the string "CALL" followed by
3. The second element in the line (when CALL is the separator)

Note: You can redirect the output into another file using:

awk -F "CALL" '{print "CALL"$2}' filename > newfilename

0

With sed:

sed -e 's/.*CALL:/CALL:/' input.txt > output.txt

If you want to edit the input file in place add the -i option.

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