What does it mean being one-to-one
By Daniel Rodriguez •
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On which interval [a,b] will the function:
$$ f(x)= \frac{x-1}{x^2 + 1} $$ be one-to-one?
What does it mean being one to one?
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$\begingroup$One-to-one means that not only there is one value of $y$ belonging to $x$ (as is commonly the case if $y$ is a function of $x$) but also the reverse: there is only one value of $x$ belonging to $y$. Can you see in the above picture where this might be the case? And how $a$ and $b$ can be determined then?
P.S. Replaces a deleted answer.
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